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Unformatted text preview: 15.2 The equation is R(τ ) = 1 N ∑ Bk Bk−τ , and the Barker sequence is (+ + + – – + –). N k =1 For R(0), we multiply the sequence with itself:
+++––+–
+ + +€ – + –
–
+ + + + + + +t
The net result is +7, which divided by N = 7 yields R(0) = 1. For all other values of
τ from 1 through 6, the value is R(τ) = 1/7. We show, as an example R(3). For this
result, the sequence is circularshifted by 3 and then multiplied by the original
sequence:
+++––+–
–+–+++–
–+–––++
The net result is 3 – 4 = –1, which divided by N yields R(3) = –1/7.
15.3 a. X6 + X5
B5 +
B4 X3 + X2
B2 ⊕ ⊕ B3 +
B1 1
B0 ⊕ b.
B5
0
1
1
1
0
0
0
0 B4
0
0
1
1
1
0
0
0 B3
0
0
0
1
1
1
0
0 B2
0
0
0
0
1
1
1
0 B1
0
0
0
0
0
1
1
1 B0
1
0
0
0
0
0
1
1 The final column is the output. Hence the first 8 bits of output are 10000011. 67 ...
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This note was uploaded on 02/20/2012 for the course ENC 3250 taught by Professor Dr.timothycerner during the Fall '11 term at UNF.
 Fall '11
 Dr.TimothyCerner

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