ENC3250 Solutions pg 67

# ENC3250 Solutions pg 67 - 15.2 The equation is R(τ = 1 N...

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Unformatted text preview: 15.2 The equation is R(τ ) = 1 N ∑ Bk Bk−τ , and the Barker sequence is (+ + + – – + –). N k =1 For R(0), we multiply the sequence with itself: +++––+– + + +€ – + – – + + + + + + +t The net result is +7, which divided by N = 7 yields R(0) = 1. For all other values of τ from 1 through 6, the value is R(τ) = 1/7. We show, as an example R(3). For this result, the sequence is circular-shifted by 3 and then multiplied by the original sequence: +++––+– –+–+++– –+–––++ The net result is 3 – 4 = –1, which divided by N yields R(3) = –1/7. 15.3 a. X6 + X5 B5 + B4 X3 + X2 B2 ⊕ ⊕ B3 + B1 1 B0 ⊕ b. B5 0 1 1 1 0 0 0 0 B4 0 0 1 1 1 0 0 0 B3 0 0 0 1 1 1 0 0 B2 0 0 0 0 1 1 1 0 B1 0 0 0 0 0 1 1 1 B0 1 0 0 0 0 0 1 1 The final column is the output. Hence the first 8 bits of output are 10000011. -67- ...
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