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Unformatted text preview: 1 2 3 4 5 6 7 8 PPM doublet int = 2H doublet int = 2H doublet int = 1H quartet (can you guess why?) int = 1H multiplet int = 1H singlet int = 3H doublet int = 6H 2. Assign the Structure of compound B: Analysis of 1H NMR spectra: Type of H shift (ppm) integration splitting tentative identification Proton NMR Spectra for Compound C. 1 2 3 4 5 6 7 8 PPM doublet int = 2H doublet int = 2H singlet int = 3H triplet int = 2H multiplet int = 3 H doublet int = 6H 3. Assign the Structure of compound C: Analysis of 1H NMR spectra: Type of H shift (ppm) integration splitting tentative identification 4. Draw the mechanism for the following reaction (use arrows to show the movement of electrons) show all lone pair and all major resonance structures. cat. HCl H 2 O H 3 C-O O-CH 3 O H O CH 3 2...
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- Spring '09
- Wang
- Proton, Mole, Nuclear magnetic resonance, Proton NMR, Deuterium, 1H NMR spectra
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