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test5

# test5 - Name Test 5 1822 November 2005 Math 119 Section 1...

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Name: Test 5 18–22 November 2005 Math 119, Section 1, Fall 2005 Jason Grout No calculators, notes, or books. Instructions: Read the questions carefully. Put your answers in the provided boxes. In order to receive full credit, you will need to neatly show your work on these pages and simplify your answers appropriately. Do not attach extra pages. If the provided space is insufficient, use the blank sides of adjacent pages. Useful Information The probability density function for a normal distribution with mean μ and standard deviation σ is f ( x ) = e - ( x - μ ) 2 / (2 σ 2 ) σ 2 π . z .00 z .00 z .00 z .00 z .00 -2.9 0.0019 -1.9 0.0287 -0.9 0.1841 0.1 0.5398 1.1 0.8643 -2.8 0.0026 -1.8 0.0359 -0.8 0.2119 0.2 0.5793 1.2 0.8849 -2.7 0.0035 -1.7 0.0446 -0.7 0.2420 0.3 0.6179 1.3 0.9032 -2.6 0.0047 -1.6 0.0548 -0.6 0.2743 0.4 0.6554 1.4 0.9192 -2.5 0.0062 -1.5 0.0668 -0.5 0.3085 0.5 0.6915 1.5 0.9332 -2.4 0.0082 -1.4 0.0808 -0.4 0.3446 0.6 0.7257 1.6 0.9452 -2.3 0.0107 -1.3 0.0968 -0.3 0.3821 0.7 0.7580 1.7 0.9554 -2.2 0.0139 -1.2 0.1151 -0.2 0.4207 0.8 0.7881 1.8 0.9641 -2.1 0.0179 -1.1 0.1357 -0.1 0.4602 0.9 0.8159 1.9 0.9713 -2.0 0.0228 -1.0 0.1587 0.0 0.5000 1.0 0.8413 2.0 0.9772 Table 1: Area under the standard normal curve to the left of z 1. (2 pts each) Determine whether each situation is discrete or continuous. If the ran- dom variable is discrete, write “discrete”. If the random variable is continous, write “continuous”. (a) Given a particular day, the random variable x is the maximum height of Utah Lake on that day.

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