{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

test5 - Name Test 5 1822 November 2005 Math 119 Section 1...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Name: Test 5 18–22 November 2005 Math 119, Section 1, Fall 2005 Jason Grout No calculators, notes, or books. Instructions: Read the questions carefully. Put your answers in the provided boxes. In order to receive full credit, you will need to neatly show your work on these pages and simplify your answers appropriately. Do not attach extra pages. If the provided space is insufficient, use the blank sides of adjacent pages. Useful Information The probability density function for a normal distribution with mean μ and standard deviation σ is f ( x ) = e - ( x - μ ) 2 / (2 σ 2 ) σ 2 π . z .00 z .00 z .00 z .00 z .00 -2.9 0.0019 -1.9 0.0287 -0.9 0.1841 0.1 0.5398 1.1 0.8643 -2.8 0.0026 -1.8 0.0359 -0.8 0.2119 0.2 0.5793 1.2 0.8849 -2.7 0.0035 -1.7 0.0446 -0.7 0.2420 0.3 0.6179 1.3 0.9032 -2.6 0.0047 -1.6 0.0548 -0.6 0.2743 0.4 0.6554 1.4 0.9192 -2.5 0.0062 -1.5 0.0668 -0.5 0.3085 0.5 0.6915 1.5 0.9332 -2.4 0.0082 -1.4 0.0808 -0.4 0.3446 0.6 0.7257 1.6 0.9452 -2.3 0.0107 -1.3 0.0968 -0.3 0.3821 0.7 0.7580 1.7 0.9554 -2.2 0.0139 -1.2 0.1151 -0.2 0.4207 0.8 0.7881 1.8 0.9641 -2.1 0.0179 -1.1 0.1357 -0.1 0.4602 0.9 0.8159 1.9 0.9713 -2.0 0.0228 -1.0 0.1587 0.0 0.5000 1.0 0.8413 2.0 0.9772 Table 1: Area under the standard normal curve to the left of z 1. (2 pts each) Determine whether each situation is discrete or continuous. If the ran- dom variable is discrete, write “discrete”. If the random variable is continous, write “continuous”. (a) Given a particular day, the random variable x is the maximum height of Utah Lake on that day.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern