Chem 161-2011 Lecture 13, Chapter 8

Chem 161-2011 Lecture 13, Chapter 8 - CHEMISTRY 161-2011...

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Chem 161-2011 Lecture 13 1 CHEMISTRY 161-2011 LECTURE 13 CHAPTER 8 MOLECULAR GEOMETRY AND BONDING THEORIES ANNOUNCEMENTS E-MAIL EXAMS Quiz 2 starts Tuesday, October 18th. The quiz will cover 6.1-7.4 Days Emphasis T (sec 50,51,55) 10/18 Chapt. 6 F (sec 52,53,54) 10/21 6.4-7.2
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Chem 161-2011 Lecture 13 2 PLAN FOR TODAY Chemical equations Interpreting and writing chemical equations Balancing chemical equations Patterns of chemical reactivity Combination reaction Decomposition reaction Combustion reaction Combustion analysis Determination of empirical formula Calculations with balanced chemical equations Moles of reactants and products Mass of reactants and products Limiting reactions Determining the limiting reactant Reaction yield Periodic trends in reactivity of the main group elements General trends in reactivity Hydrogen (1s 1 ) Reactions of the active metals Group 1A Elements (ns 1 , n 2) Group 2A Elements (ns 2 , n 2) Reactions of other main group elements Group 3A Elements (ns 2 np 1 , n 2) Group 4A Elements (ns 2 np 2 , n 2) Group 5A Elements (ns 2 np 3 , n 2) Group 6A Elements (ns 2 np 4 , n 2) Group 7A Elements (ns 2 np 5 , n 2) Group 8A Elements (ns 2 np 6 , n 2) Comparison of Group 1A and Group 1B elements
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Chem 161-2011 Lecture 13 3 ET note: Not everything goes through moles, e.g., volume to grams, grams to volume, atoms to molecules, molecules to atoms. ZUMDAHL 6 TH EDITION CHEM 161-2007 RECITATION 4th WEEK CHAPTER 5 - STOICHIOMETRY moles A moles B atoms molecules (or atoms if particle is an a t o m ) M B or V B g B or MW B V B M A or V A V A g A or MW A MOLES ARE AT THE CENTER (FOR CONVERSIONS, WORK THROUGH MOLES) MW (D = g/V) mol A = M A L A moles = PV/RT for gases (molecules x atoms/molecule = atoms) (moles A = g A /MW A ) mol B = M B L B (moles B = g B /MW B ) (D = g/V) (moles x Avog. No. = molecules (or atoms)) %A % B Empirical formula Molecular formula (MW/EW) x Emp form = molec form moles = g/MW PV = nRT moles = M x V P 1 V 1 /n 1 T 1 =P 2 V 2 /n 2 T 2 g/MW = M x V 6.022x10 23 molecule/mole D = g/L MW A or AW A = g A /mole A moles A = g A /MW A
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Chem 161-2011 Lecture 13 4 BALANCING CHEMICAL EQUATIONS Hill & Petrucci CHAPTER 3 - STOICHIOMETRY BALANCING CHEMICAL REACTIONS Stoichiometry: Greek stoikheion element + metry: measurement ; the numerical relationships of reactants and products involved in chemical reactions, using numerical coefficients A chemical equation is based on experiments. Read the equation as, e.g., “Benzene and oxygen react to produce carbon dioxide and water,” or “Benzene and oxygen yield carbon dioxide and water.” Virtually all elements are written in their monatomic state, e.g., iron is “Fe”. Exceptions are H 2 , N 2 , O 2 , F 2 , Cl 2 , Br 2 and I 2 . Phosphorous and sulfur are usually written as P4 and S8, but usually P and S. Reactants is the starting substances in a reaction, and appear on the left side of the chemical equation. Products is the substances formed in a reaction, and appear on the right side of the chemical equation.
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Chem 161-2011 Lecture 13, Chapter 8 - CHEMISTRY 161-2011...

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