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Unformatted text preview: Slab 1 Slab 2 + b c E E 2 1 1 2 1 2 Physics 4321 Homework Set 8 October 27, 2008 Due: November 3, 2008 1. The space between the plates of a parallel plate capacitor is filled completely with two slabs of dielectric material, each having thickness a . Slab 1 has a dielectric constant of 2, whereas slab 2 has a dielectric constant of 3/2. The free charge density on the top plate is + and on the bottom plate. There is no thickness between the slabs or between the slabs and the conducting plates. (a) Find the electric displacement D in each slab. (b) Find the electric field E in each slab. (c) Find the polarization P in each slab. 2. For the configuration in problem 1, (a) find the potential difference between the plates. (b) Find the location and the amount of all bound charge. (c) Use the total charge to recalculate the electric field in each slab. 3. A sphere of linear dielectric material has embedded in it a uniform free charge density . Find the potential at the center of the sphere (relative to infinity) if its radius is...
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This note was uploaded on 02/20/2012 for the course PHYS 1101 taught by Professor Lowellwood during the Fall '10 term at University of Houston.
- Fall '10