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Lab #14

Lab #14 - JaclynAucoin Experiment#14 Summer2003...

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Jaclyn Aucoin Experiment #14 Characterization and design of an ac variable-gain amplifier Summer 2003 6/23/2003 Lab Partner: Steve Smith
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1. Design and construct the circuit shown in Fig. 1: What values did you choose? Vcc=10V, Vee=-10V, Re=10k, Rb=10k, Ie=Ic=Ve-Vee/Re=0.93mA, Vout=Vcc-IcRc, Rc=4.7k. What is the dc voltage at the base, and how is it determined? It was -57.84mV which is approximately 0. This is due to the base being grounded through a resistor. There is very little current flowing from base to emitter. Vb=-IbRb. What value did you choose for Ce? We chose 1µF because Z Ce =1/ (2∏RC)=15.9Ω for C=1µF. We wanted Z Ce to be less than 1/10Re which is 1000. What is its impedance? 15.9Ω as shown in previous answer. 2. What is the value of R 1 for a gain of -10? It was measured to be 409Ω.
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Explain any difference from your measured value. The theoretical value is taken from the equation Gain=-Rc/Re. Setting the Gain=-10 and Rc=4.7k and solving for Re you get Re=470Ω. This is a very small difference.
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Lab #14 - JaclynAucoin Experiment#14 Summer2003...

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