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HomeworkSolutions2 - SP15(b 1.50 bar 0.0475 m 3(c-15.4 kJ...

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Thermodynamics ME 200 – Spring 2012 Numerical Answers to Homework Problems Lectures 11 through 22 3.40 (a) T = 100.56°F, v = 0.2675ft 3 /lb; (b) p = 18.85 lbf/in 2 , h = 615.2 Btu/lb; (c) p = 47.60 lbf/in 2 , h = 108.80 Btu/lb 3.44 (a) T = 133.6°C, u = 2196.7 kJ/kg; (b) p = 7.467 MPa, u = 2678.0 kJ/kg; (c) v = 0.01020 m 3 /kg, h = 3192.3 kJ/kg; (d) p = 1.228 kPa, h = 2371 kJ/kg; (e) v = 1.1011x10 -3 m 3 /kg, u = 673.71 kJ/kg 3.53 (a) 50°C; (b) 72.91 kJ/kg SP11 (b) 0.0280 kg; (c) W 12 = 4.74 kJ, Q 12 = 42.2 kJ; (d) 3.57x10 -3 m 3 3.83 (a) p 1 = 200 lbf/in 2 , p 2 = 160 lbf/in 2 ; (b) 0.054 lb; (c) -1.54 Btu; (d) -12.22 Btu 3.87 295.9 K SP12 35.5°F 3.101 (a) 24%; (b) 0.40%; (c) 3.5%; (d) Z = 1: air is closely modeled as an ideal gas at this state; (e) 37.4% 3.108 From Table A-18: T = 60°C = 333.15 K; From Figure A-1: T = 52.5°C = 325.6 K Comparison: 2.3% (in K), 12.5% (in °C) SP14 (a) 0.03293 m 3 /kg; (b) 0.0332 m 3 /kg; (c) 0.0391 m 3 3.123 (a) -1.06 kJ; (b) 3.73 kJ 3.128 (a) 250 K; (b) -126.8 kJ
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Unformatted text preview: SP15 (b) 1.50 bar, 0.0475 m 3 ; (c) -15.4 kJ 4.6 1200 lb 4.11 (a) 20.05 lb/s; (b) 2212.2 ft 3 /lb; (c) 14.6 ft/s SP16 (a) 81.2 kg/s, 50.9 m/s; (b) 61.2 kg/s, 65.6 m/s; (c) 4.07 m/s 4.23 -650 kW 4.27 (a) v 1 = 55.38 m/s, v 2 = 251.73 m/s; (b) 0.04 kg/s SP17 (a) 23.1 kg/s; (b) 76.6 m/s; (c) 4,690 kW 4.31 (a) 600.8 m/s; (b) A 1 = 22.5 cm 2 , A 2 = 7.11 cm 2 4.39 400 lbf/in 2 SP18 (a) A inlet = 2.13 ft 3 , A exit = 0.445 ft 3 ; (b) -243.8 Btu/s 4.41 6927 kW 4.53 -26.6 kW 4.65 -0.05 hp, -2.12 Btu/min SP19 (a) 2.66 kg/s; (b) 0.0745 m 3 /s; (c) -207 kW 4.70 (a) 0.9; (b) -1.12 kW 4.77 (a) 7.96 kg/min; (b) 8.1 kJ/kg SP20 4.91 99.6°C ≤ T 2 ≤ 151°C; 0.949 ≤ x 1 ≤ 1.0 4.97 (a) 4.67 lb/min; (b) -1.41 hp SP21 5.3 (a) Possible; (b) Possible; (c) Impossible; (d) Indeterminate; (e) Possible; (f) Impossible; (g) Indeterminate 5.6 (a) False; (b) False; (c) False; (d) True 5.8 Not provided SP22...
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