HW 15 Solution

# HW 15 Solution - PROBLEM 5.2 Locate the centroid of the...

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Unformatted text preview: PROBLEM 5.2 Locate the centroid of the plane ma shovm‘ SOLUTION A,mm1 E mm 1 ix60X75=2250 40 2 105 x 7:5 = 7316 112.5 E 10125 . 975 900 351600 m m 915 900 mm3 _ Then Xz—z— . orX=96.4mm‘ EA 10 125 m3 -- 3 2%=% 0r1r_'=34.?mm‘ PROBLEM 5.5 Locate the centroid of the plane area shown. L—mmm—vl ’ SOLUTION 12.0 x 200 = 24 000 2 If?) = 5554.9 18 345 u £34 90540 — = =& or X:49.4mm 4 Then 1? , Ed 18 345 111.111— 2 A _ - 3 and Exam - EA 18345111111 __ . P ROBLEM 5.1 1 Locate the centroid ofthe plane area shown. SOLUTIO N First note that symmetry implies Then b1N:EN5\BN‘:a "d 5H . r11: Him, a: = 45° if = Ersirla _ 2[.2\E‘|_'5i11[:) . _ ._. = mm' . “ 3a 3H?) m .4, in2 j y, in. 5A. in3 . 1 \ i i 1 E[4}{3} = 6 | 6 : yr '2 _ 2 ﬂzﬁ] = 6.283 2 — y = 0.3024 L899? 3 —%{4}{2) = —4 0.666? i ~2.66? 2 3.233 5.2330 in : 237A }7[s.233 if) = 5.2330 in} ><I n 0'1 or 1" =0.632 in. “ E ...
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## This note was uploaded on 02/17/2012 for the course CEE 240 taught by Professor Chang during the Spring '08 term at UMass (Amherst).

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HW 15 Solution - PROBLEM 5.2 Locate the centroid of the...

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