mudzm6 - Muddy Card Responses Lecture M6 Can you re-explain...

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Muddy Card Responses Lecture M6 Can you re-explain why there's a moment now? (see picture) N 5 m A B C 20 0 10 m Not sure what the question is. Here are a couple of thoughts. The reaction at A and B are force reactions (but not pure moments). However, the force of 200N has a moment about both points A and B, so the reaction force at A must have a moment about B that is equal and opposite to that due to the load, and similarly for the moment due to the reaction at A and the load about point B. In the section method, why is the moment arm for F ED L ? See figure below. The moment arm of F ED about B is the height of point E about the bar AB, which is a length L. This represents the perpendicular distance of the line of action of the force F ED from point B.
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Could you explain which moments you used in the last example? See picture above. By taking moments about point B, we eliminate F EB and F AB , which both pass through point B and therefore have no moment arm about it. The only two forces acting on the section which have a moment about B are F ED (which we want to find) and the reaction at point A, of P. Not quite clear on the end of the last example why are we taking moments around
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mudzm6 - Muddy Card Responses Lecture M6 Can you re-explain...

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