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Conservation of Linear Motion Lab

# Conservation of Linear Motion Lab - ground at the same time...

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Conservation of Linear Motion Lab Name: Poojan Patel Date: 11/29/10 Lab Partners: Mike Dunleavy, Mike Borkowski, and Patrick Sheil Purpose: The purpose of this lab was to find out through experimentation that momentum is conserved in a linear collision. Materials: Clamp 2 tables Marker Marbles Scale Data and Results: Part B Mass (kg) Small marble 0.0054 Big marble 0.0531 Height to the ground (m) 1.46 Height of the ramp (m) 0.115 Time (seconds) 0.5466 Change in x (meters) 0.64 Velocity (m/s) 1.17 Part A Mass (kg) Marble 1 0.0056 Marble 2 0.0054 Height to the ground (m) 1.46 Height of the ramp (m) 0.115 Time (seconds) 0.5466 Change in x (meters) 0.57 Velocity (m/s) 1.04 Formulas: 1) =1/2at 2 2) M1V1 i +M2V2 i = M1V1 f +M2V2 f 3) V x = X/t

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Conclusion: There were two parts to this lab. The first part of the lab involved two marbles that were about the same mass that collided. The second part of the lab involved two marbles with completely different masses that collided. In the first part of the lab, both marbles hit the
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Unformatted text preview: ground at the same time because a marble that drops straight down hits the ground at the same time as a ball that travels like a projectile. In the second part of the lab, the smaller marble traveled even further than the smaller marble in part 1 and the big marble ended up in about the same place. The smaller marble traveled further in part two because it was hit by a greater mass. In order to find out whether or not momentum was conserved I used the formula m 1i v 1i +m 2i v 2i = m 1f v 1f +m 2f v 2f . We used a scale to find the mass of each marble. In order to find the velocity we used the formula V x = ∆ X/t. After plugging-in the values for velocity and mass we figured that in both parts momentum was basically conserved. Any differences in momentum were due to friction. In a frictionless environment momentum would have been conserved perfectly....
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