Recitation Problems  for Matlab Week 1 and Week 2

Recitation Problems  for Matlab Week 1 and Week 2

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Poojan Patel MATLAB 1/25/2012 Recitation Problems for Matlab Week 1 Problem #1 Practice exercises 2.3 1) >> 6/6+5 ans = 6 2) >> 2*6^2 ans = 72 3) >> (3+5)*2 ans = 16 4) >> 3+5*2 ans = 13 5) >> 4*3/2*8 ans = 48 6) >> 3-2/4+6^2 ans = 38.5000 7) >> 2^3^4 ans =
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Poojan Patel MATLAB 1/25/2012 4096 8) >> 2^(3^4) ans = 2.4179e+024 9) >> 3^5+2 ans = 245 10) >> 3^(5+2) ans = 2187 11) >> (5+3)/(9-1) ans = 1 12) >> 2^3-(4)/(5+3) ans = 7.5000 13) >> (5^(2+1))/(4-1) ans = 41.6667 14) >> 2*(10)/(3) ans = 6.6667 15) >> [5+6*(7/3)-2^2]/[(2/3)*(3/3*6)]
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Poojan Patel MATLAB 1/25/2012 ans = 3.7500 Practice Exercises 2.4 1) >> a= [2.3 5.8 9] a = 2.3000 5.8000 9.0000 2) >> sin(a) ans = 0.7457 -0.4646 0.4121 3) >> a+3 ans = 5.3000 8.8000 12.0000 4) >> b= [5.2 3.14 2] b = 5.2000 3.1400 2.0000 5) >> a+b ans = 7.5000 8.9400 11.0000 6) >> a.*b ans = 11.9600 18.2120 18.0000 7) >> a.^2 ans =
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Poojan Patel MATLAB 1/25/2012 5.2900 33.6400 81.0000 8) >> c= [0 1 2 3 4 5 6 7 8 9 10] c = 0 1 2 3 4 5 6 7 8 9 10 9) >> c= [0 2 4 6 8 10] c = 0 2 4 6 8 10 10) >> linspace(10, 20, 6) ans = 10 12 14 16 18 20 11) >> logspace(1, 2, 5) ans = 10.0000 17.7828 31.6228 56.2341 100.0000 Problem #2 >> a= [1 2 4 5] a = 1 2 4 5 >> b= [5 4 2 1] b = 5 4 2 1 >> a+10 ans =
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Poojan Patel MATLAB 1/25/2012 11 12 14 15 >> a*10 ans = 10 20 40 50 >> a+b ans = 6 6 6 6 >> a.*b, ans = 5 8 8 5 >> a./b, ans = 0.2000 0.5000 2.0000 5.0000 >> a+1./b, ans = 1.2000 2.2500 4.5000 6.0000 >> 1./a+b ans = 6.0000 4.5000 2.2500 1.2000 >> a.^2, ans = 1 4 16 25 >> a+b.^2,
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Poojan Patel MATLAB 1/25/2012 ans = 26 18 8 6 >> a.^2./a, ans = 1 2 4 5 >> a.^2./b, ans = 0.2000 1.0000 8.0000 25.0000 >> (a.^2)./b, ans = 0.2000 1.0000 8.0000 25.0000 >> a.^(2./b), ans = 1.0000 1.4142 4.0000 25.0000 >> a./b.^2, ans = 0.0400 0.1250 1.0000 5.0000 >> (a./b).^2 ans = 0.0400 0.2500 4.0000 25.0000 After looking at and using the following operations: + */ ^, I can conclude that each of the operations are important in their own way and serve a different purpose. No one operation has precedence over another because they all serve a very important purpose in matlab.
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Poojan Patel MATLAB 1/25/2012 Problem # 3 Code examples pp. 32-40 week-1 lecture notes >> x= 0: 0.2: 1 x = 0 0.2000 0.4000 0.6000 0.8000 1.0000 >> x= linspace(0,1,6) x = 0 0.2000 0.4000 0.6000 0.8000 1.0000 >> x= 0: 0.3: 1 x = 0 0.3000 0.6000 0.9000 >> x= 0: 0.4: 1 x = 0 0.4000 0.8000 >> x= 0: 0.7: 1 x = 0 0.7000 >> x= [2, 5, -6, 10, 3, 4]; >> double x[6] ans = 120 91 54 93 >> x= [2, 5, -6, 10, 3, 4] x =
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Poojan Patel MATLAB 1/25/2012 2 5 -6 10 3 4 >> length(x) ans = 6 >> x(1) ans = 2 >> x(3) ans = -6 >> x(end) ans = 4 >> x(end-3:end) ans = -6 10 3 4 >> x(3:5) ans = -6 10 3 >> x(1:3:end) ans = 2 10 >> x(1:2:end)
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Poojan Patel MATLAB 1/25/2012
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