University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 3.55: a) With 0 = 45 , Eq. (3.27) is solved for v0 = gx 2 x- y . In this case, y = -0.9 m is the change in height. Substitution of numerical values gives v0 = 42.8 m/s . b) Using the above algebraic expression for v0 in Eq. (3.27) gives x y = x- 188 m (188.9 m) Using x = 116 m gives y = 44.1 m above the initial height, or 45.0 m above the ground, which is 42.0 m above the fence. 2 ...
View Full Document

Ask a homework question - tutors are online