第七章习题答

第七章习题答

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解: AgCl = Ag + + Cl - Ag + + 2NH 3 H 2 O [Ag(NH 3 ) 2 ] + + Cl - + 2H 2 O = + AgCl (s) + 2NH 3 H 2 O (aq) [Ag(NH 3 ) 2 ] + (aq) + Cl - (aq) + 2H 2 O (aq) Δ f G θ m -109.8 -263.8 -17.2 -131.26 -237.19 Δ r G θ m =[(-17.2)+(-131.26)+2*(-237.19)]-[(-109.8)+2*(-263.8)] =14.56 kJ/mol x-0.1 0.05 0.05 K=0.05*0.05/(x-0.1) 2 Δ r G θ m = - RTlnK R=8.314 T=298.15K x=1.04 mol/L AgCl (s) + 2NH 3(l) = [Ag(NH 3 ) 2 ] + (aq) + Cl - (aq) Δ f G θ m -109.8 -26.21 -17.2 -131.26 Δ r G θ m = 14.56 kJ/mol 解答同上 K sp (AgCl)= 1.8*10 -10 K 1.12*10 7 [Ag(NH 3 ) 2 ] + K = K sp * K K=2.81*10 -3 K=2.02*10 -3 x= 1.21 mol/L AgCl (s) + 2NH 3(g) =[A g (NH 3 ) 2 ] + (aq) + Cl - (aq) Δ f G θ m -109.8 -16.5 -17.2 -131.26 Δ r G θ m = -5.56 kJ/mol x=0.12 mol/L 这里我后来也找到了液氨的数据,可以与水合氨相吻合。 3 .有六种异构体,分别有 M 代表金属离子, A B C 代表三种配体: M B C C B A A M A B C C B A M A B C C
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第七章习题答

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