普通化学05

普通化学05

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浙浙浙浙 2004–2005 浙浙 浙浙 浙浙浙 浙浙浙浙 浙浙浙浙浙浙浙浙浙 开开开开开 开开开 开开开开开开开开开开开开__开开开开开 ___开开 开开开开开_2005_ _1_ _17_ 开,开开开开开 120 开开 开开开开开 _____ 开开开 开开开 ________ 开开 1 2 3 4 5 6 7 8 9 10 开 开 开开 开开开 1.开开开 开16 开开 开1开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开开 Q开 开0开W( )0开 U( )0开 H开 开0 开 S开 开0 开 [开开开开开开开开 >开= 开 < ] 开2开开开开开开开开开开开开开开 W =开 开开 开3开开开开开开开开开开开开开开开开开开开开开开 开开 开4开开开开开开开开开 k 开开开开开开开开开 开开 开5开开开开[Ni(NH 3 ) 2 ] 2+ 开 K 开开 = a开[Ni(CN) 2 ]开 K 开开 = b开开 开开[Ni(NH 3 ) 2 ] 2+ + 2 CN - [Ni(CN) 2 ] + 2 NH 3 开开开开开 K 开开 开开 开6开开开开 开Sn 4+ /Sn 2+ 开= 0.15V, ϕ θ 开Zn 2+ /Zn开= -0.76V, ϕ θ 开Ce 4+ /Ce 2+ 开= 1.16V, ϕ θ 开Br 2 /Br - 开= 1.07V, ϕ θ 开Fe 3+ /Fe 2+ 开= 0.77V开开开开开开开开开开开开开开 Br - 开开开 Br 2 开开开 开开 开7开开开开开开开开开开开开开开开开开开开开开开 开开 开8开开开开开开开开开开开开开
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