Midterm Exam I_Answer

Midterm Exam I_Answer - Chemistry 6C; Midterm Examination...

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Chemistry 6C; Midterm Examination I; April 20, 2011 Total points 100 (5pts x 20) (Maximum 20% of the final grade) Name: Student ID: Section ID: Relevant Formulas: E cell = E° cell − RT ln Q nF E cell = E° cell − 0.05916 V log Q (at 298.15 K) n ∆G = −nFE cell ∆G 0 = −RT ln K ∆G = H − TS ∆G = ∆G 0 + RT ln Q S = k B ln W S sys =q rev /T S sur =∆H sys /T Useful constants: F = 96500 C/mol e NA = 6.02 x 10 23 units/mol 1
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kB = 1.38 x 10 23 J/K R = 8.314 J/mol•K 1. Which substance below should have the highest entropy at 298K? a. 5H 2 O (g) b. 7NH 3(l) c. 4H 2 SO 4(g) d. 5H 2(g) 2. For the reaction 2C(s) + H 2 (g) C 2 H 4 (g), H = 52.3KJ/mol and S = -53.07J/(K*mol). The reaction will be spontaneous at: a. All temperatures b. Temperatures above 985K c. No temperatures d. Temperatures below 985K 3. The entropy of a pure, perfect crystal is zero at 0 K. How many accessible microstates are there in such a system? a. Zero b. One c. It depends on the size of the crystal d. There is no connection between the number of microstates and the entropy 4. If the G of a reaction is negative, then a. The forward reaction is spontaneous. b. The reaction is in equilibrium. 2
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c. The reverse reaction is spontaneous. d. Concentrations of the products and reactants are identical. 5.
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Midterm Exam I_Answer - Chemistry 6C; Midterm Examination...

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