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Unformatted text preview: 1 Math 2331 HW 3 Key Problem : (3 points each) Let 1 2 5 , . 3 4 2 A B = = 1 2 5 3 4 2 2 3 4 2 6 6 A B  = = 1 2 5 5 4 3 4 2 15 6 AB = = 5 1 2 5 10 2 3 4 6 8 BA = = 1 4 2 4 2 2 1 1 1 3 1 3 1 3 / 2 1/ 2 1 4 2 3 2 A = = =  ⋅ ⋅ 1 2 2 1/ 5 1 1 5 5 1/ 2 5 2 10 B = = = ⋅ OR: Since B is a diagonal matrix, you can say: 1 1/ 5 1/ 2 B = directly using the formula for finding the inverse of a diagonal matrix. Homework is graded out of 45+5=50points. (5 points to everyone for turning in hw.) 2 2.4.1: (5 points – 1 point each) BA: defined, (5x3)(3x5)=5x5...
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This note was uploaded on 02/21/2012 for the course MATH 2331 taught by Professor Staff during the Spring '08 term at University of Houston.
 Spring '08
 Staff
 Math, Linear Algebra, Algebra

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