problem03_56

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.56: The equations of motions are 2 0 2 / 1 ) sin ( gt t α v y - = and t α v x ) cos ( 0 = , assuming the match starts out at 0 = x and 0 = y . When the match goes in the wastebasket for the minimum velocity, D y 2 = and D x 6 = . When the match goes in the wastebasket for the maximum velocity, D y 2 = and D x 7 = . In both cases, . 2 / 2 cos sin = = α α . To reach the minimum distance: t v D 0 2 2 6 = , and 2 2 1 0 2 2 2 gt t v D - = . Solving the first equation for t gives 0 2 6 v D t = . Substituting this into the second equation gives ( 29 2 2 6 2 1 0 6 2 v D g D D - = . Solving this for
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