HW3 Solution

HW3 Solution - EE321, Homework 3 Problem 1 From minimum...

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Unformatted text preview: EE321, Homework 3 Problem 1 From minimum cost solution in class N 260 := d 8.3788 10 2 := g 13.069 10 3 := w 1.8361 10 2 := d s 8.9184 10 2 := w s 8.9184 10 2 := 4 10 7 := i 40 := L des 5 10 3 := r 5000 := Recomputing the reluctance R 2g w d 2 w s 2w + ( ) 2d s + r w d + := R 13.565 10 6 = a) To find the inductance L N 2 R := L 4.984 10 3 = b) To find the flux density in the magnetic material Ni R = BA = so B m N i R w d := B m 498.361 10 3 = c) The flux density in the air gap is the same (areas assumed equal) B g B m := B g 498.361 10 3 = d) The field intensity in the magnetic material is H m B m r := H m 79.317 10 = e) The field intensity in the air gap is H g B g := H g 396.583 10 3 = f) The percentage difference between this calculated inductance and the design value is L L des L des 100 329.835 10 3 = percent Problem 6 Solution (I know this is out of order, but is is a convenient point)...
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HW3 Solution - EE321, Homework 3 Problem 1 From minimum...

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