{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW4 Solution

# HW4 Solution - EE321 Spring 2011 Homework 4 Problem 1 1 2...

This preview shows pages 1–3. Sign up to view the full content.

EE321, Spring 2011 Homework 4 Problem 1 W c 1 2 5 2sin 8 θ rm ( ) + ( ) i 2 = T e 8 cos 8 θ rm ( ) i 2 = Problem 2 We may express the system as λ 1 λ 2 5 3 5 x 2 + 7 5 x 2 + 2 i 1 i 2 = which is of the form λ 1 λ 2 L i 1 i 2 = where L is independent of both current and flux linkage. Thus, this system is magnetically linear. However, because the partial of lamba 2 with respect to i1 isn't equal to the partial of lambda 1 with respect to i2, the system is not conservative. Problem 3 The given equation is in the linear form λ Li = therefore f e x W c = x 1 2 i T L i =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
f e 1 2 i T x L i = 1 2 i 1 i 2 i 3 ( ) 0 2 1 x + ( ) 2 0 2 1 x + ( ) 2 0 0 0 0 0 i 1 i 2 i 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}