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final exam solution

final exam solution - EE321 Spring 04 Final Exam Solution...

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W c 12.5 = W c2 10 = W c2 0 2 i 2 1 4 i 2 + d = W c1 5 2 = W c1 0 1 i 1 5 i 1 d = Trajectory 1. λ 2 i 1 4 i 2 + = λ 1 5 i 1 3 i 2 + = Problem 2 R l µ A = F ab R Φ = F ab l Φ µ A = B Φ A = Φ B A = Φ S B d = F ab Bl µ = H B µ = F ab H l = F ab a b l H d = Problem 1 EE321 - Spring 04 - Final Exam - Solution
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i f 1000 15.4 = i f v dc v fsw r f i fbar L ff d 1 f sw := i fbar 7.325 = i fbar v fbar r f := v fbar 14.65 = v fbar v dc v fsw ( ) d v fd ( ) 1 d ( ) + := v fd 0.75 := f sw 10 10 3 := r f 2 := v fsw 1.5 := d 0.8 := L ff 20 10 3 := v dc 20 := Problem 3 The co-energy is a function of trajectory - therefore it is not conservative W c 14.5 = W c 11 2 9 + = W c 0 1 t 11t d 0 1 2t ( ) 9t d + = t will go from 0 to 1 i 2 2t = i 1 t = Tractory 2
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i bs α sin β t ( ) = i as cos β t ( ) = Now we have that W bs 5 4 sin 4 φ sm ( ) = W as 5 4 cos 4 φ sm ( ) = First we compute the winding functions...
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