Exam3 - EE321 Exam 3 Spring 2006 Handy Identities 2 1 3 2 cos 2 3 3 2 sin − = − − = − π π 7 10 4 − = π µ H/m Important Note Since

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Unformatted text preview: EE321 Exam 3 Spring 2006 Handy Identities: 2 / 1 ) 3 / 2 cos( 2 / 3 ) 3 / 2 sin( − = − − = − π π 7 10 4 − = π µ H/m Important Note: Since calculators are not allowed, you can have π in your answer to any problem. ( ) ( ) ( ) dx du u u dx d dx du u u dx d B A B A B A B A B A B A B A B A B A B A B A B A B A B A B A cos ) sin( sin ) cos( ) sin( ) sin( 2 1 cos sin ) cos( ) cos( 2 1 sin sin ) cos( ) cos( 2 1 cos cos sin sin cos cos ) cos( sin cos cos sin ) sin( = − = − + + = + − − = − + + = = ± ± = ± ∓ 1.) 8 pts. Physically speaking, what does the winding function tell us? 2.) 15 pts. Consider a machine with the winding pattern below. How many poles does the machine have ? Find the discrete winding function. T as N ] 5 5 5 5 5 5 5 5 5 5 5 5 [ − − − − − − = 3.) 15 pts. The conductor density (positive out) of a machine is given by ) 12 cos( 50 ) 4 cos( 100 sm sm as n φ φ − = How many poles does the machine have? Compute the winding function....
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This note was uploaded on 02/19/2012 for the course ECE 321 taught by Professor Staff during the Spring '08 term at Purdue University-West Lafayette.

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Exam3 - EE321 Exam 3 Spring 2006 Handy Identities 2 1 3 2 cos 2 3 3 2 sin − = − − = − π π 7 10 4 − = π µ H/m Important Note Since

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