problem03_57

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.57: The range for a projectile that lands at the same height from which it was launched is g α v R 2 sin 2 0 = , and the maximum height that it reaches is g α v H 2 sin 2 2 0 = . We must find R when D H = and gD v
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Unformatted text preview: 6 = . Solving the height equation for g α gD D 2 sin 6 2 , sin = α , or 2 / 1 ) 3 / 1 ( sin = . Then, g gD R ) sin(70.72 6 ° = , or D D R 2 4 6569 . 5 = = ....
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