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3.57:
The range for a projectile that lands at the same height from which it was launched
is
g
α
v
R
2
sin
2
0
=
, and the maximum height that it reaches is
g
α
v
H
2
sin
2
2
0
=
. We must find
R
when
D
H
=
and
gD
v

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**Unformatted text preview: **6 = . Solving the height equation for g gD D 2 sin 6 2 , sin = , or 2 / 1 ) 3 / 1 ( sin = . Then, g gD R ) sin(70.72 6 = , or D D R 2 4 6569 . 5 = = ....

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