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Ch. 7_100510

# Ch. 7_100510 - Discussion Section 227 Chapter 7 Probability...

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Discussion Section 227 10/05/10 Chapter 7: Probability The normal curve has known m under the curve and use it to co The Z score distribution forms a from the population between + Using the Unit Normal Table 1. The table gives us propo 2. The table has 4 columns A. Z score B. proportion in body C. proportion in tail D. proportion between 3. To find the probability o to a Z score and then lo 4. Because the distribution table. ty, Z scores, and the Sampling Distribution of the M mathematical properties and so it is possible to comp ompute probabilities. a normal curve. What is the probability of obtaining +1 and -1 SD? .68 ortions of areas under the normal curve for every Z s (from left to right): n mean and Z of obtaining any individual score, we first convert th ook up the appropriate proportion in the Unit Norma n is symmetrical, we can ignore negative signs when Mean pute the area an individual score. he raw score al Table. n using the

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Example 1 : Population with µ = 84, σ = 6 What is the probability of obtain 1. Draw sketch: a. Draw normal curve. b. Add in the mean an c. Add the score of int d. Shade the appropria 2. Convert raw score to Z s Z = (96-84)/6 = 2 3. Look up proportion in th we don’t care about ne (proportion in the tail). Now we write the state P(Z>2) = .0228 or 2.28% Example 2: In the same distribution (µ=84, 1. Draw a sketch: ning a score of more than 96? P(X>96) .
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Ch. 7_100510 - Discussion Section 227 Chapter 7 Probability...

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