Chapter10_STAT515Fall2011

# Chapter10_STAT515Fall2011 - Solution to some problems in.22...

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Solution to some problems in chapter 10 10.22. a. The completed ANOVA table is given in Table 1. Table 1: The complete ANOVA table for Problem 10.22 . Source df SS MS F Treatments 6 18.4 3.0667( 18 . 4 / 6) 4 . 0051( 3 . 0667 / 0 . 7657) Error 35(=41 - 6) 26 . 8(= 45 . 2 - 18 . 4) 0.7657( 26 . 8 / 35) Total 41 45.2 b. Because the degrees of freedom of SST is 6, there are 7 treatments. c. The F critical value for this test is F 0 . 10 (6 , 35) . From Table VIII in Appendix A in the textbook, we ﬁnd F 0 . 10 (6 , 30) = 1 . 98 and F 0 . 10 (6 , 40) = 1 . 93 . Therefore 1 . 93 < F 0 . 10 (6 , 35) < 1 . 98 . As shown in Table 1, the value of F -statistic is 4.0051, which is greater than F 0 . 10 (6 , 35) . Hence we reject H 0 (all population means are equal) at signiﬁcance level 0.1 and conclude that there is a signiﬁcant diﬀerence among the population means. d. According to Table XI in Appendix A in the textbook, F 0 . 01 (6 , 30) = 3 . 47 and F 0 . 01 (6 , 40) = 3 . 29, both smaller than the value of the

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Chapter10_STAT515Fall2011 - Solution to some problems in.22...

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