problem03_59

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.59: a) In Eq. (3.27), the change in height is h y - = . This gives a quadratic equation in x , the solution to which is [ ] . 2 sin sin cos cos 2 tan cos 0 2 2 0 0 0 0 0 0 2 0 0 2 0 2 0 gh v v g v v gh g v x + + = + = α If 0 = h , the square root reduces to 0 0 sin v , and R x = . b) The expression for x becomes ] 98 . 0 sin sin [ cos m) 2 . 10 ( 0 2 0 2 0 + + + = x The angle ° = 90 0 corresponds to the projectile being launched straight up, and there
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Unformatted text preview: is no horizontal motion. If = , the projectile moves horizontally until it has fallen the distance h . c) The maximum range occurs for an angle less than ° 45 , and in this case the angle is about ° 36 ....
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