Gauss Elimination - 1/3 Gaugg {/xmmaf/OVI [mm/Me M. kac 4...

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Unformatted text preview: 1/3 Gaugg {/xmmaf/OVI [mm/Me M. kac 4 Men; lflOw 17; use Gar/$5 E/Immkhon +0 517va 61 57g+€w~ o-F [Meow CqUA‘I'iamSZ Gui/ch: ZK+4\/ 7 l 3x - \/ : Z. X My gala-Hon: Thesc +109 é‘l‘ofld‘lons describe S‘H‘GISLOL fines. The solu‘h'cn is We pond— (Xf y") od‘ on;th The ma lmes Cross. | | | .1 .05 0 0.5 as x x Tl"c W0$+ COHVCWI'ZMTL way 7"0 So/vc' Sys’rcms 070 [linear (aluad'fows ls ‘fb USC chchr'tx adj-55¢“: Writ~ TIM PmHew in Marl"le “Who”: Z 4]{x : g I Y . “s -I ‘/ L3 2/3 New, Problem m aU§:MO/\\Lff{ git/1A: [i .T :1 Nbbu’ use Irow apt’ra’nons To Converf ‘Hmls €KPV‘CSSlovx +0 V‘ow Ecbdoh firm: ‘22.:111— 3212‘ [Z 4. l/L TL: {afl- SML’. I3 I}! “VA V‘OLQ €CL|€[DV\ 90mm V 1“ CTUNHOA Form) +‘LH5 I5; X 'k 27’ = t/L <.{ Solvt By \/ = ' V14 subswuhsn 3/3 ,I X-Zxrzr Z I __,=(’ x 7 z. rLL‘l—z—‘Z X 1*7‘/4+«4l4 ‘X‘g/I‘t => 9/r¢=o.e42-ge Ham's 1.1m Sawflah (ISM? Madrlxcmf: Solve the example problem using matrix notation: at: :1 we _ 1 0.64286 . a -b : <= Solution vector —0.07143 + “WWW TMAM use 5405 e/thnimdwon) The. WIN-kc”! Soto‘t‘tom (2:65 Med-wa adgebm'. mm #131 $310935: ...
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This note was uploaded on 02/21/2012 for the course MET 581 taught by Professor Staff during the Fall '08 term at Purdue University-West Lafayette.

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Gauss Elimination - 1/3 Gaugg {/xmmaf/OVI [mm/Me M. kac 4...

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