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Unformatted text preview: equilibrium with dissolved solute-A supersaturated solution contains more than the equilibrium concentration of a solute-Supersaturated solutions are unstable Concentration Units-The amount of solute relative to the volume of a solution or the amount of solvent in a solution is called concentration o Molarity M = moles of solutes/liters of solution o Mole fraction X o Parts per million ppm(suba) = mass of A/ mass of solution x 10^6 o Parts per billion ppb(suba) = mass of A/mass of solution x 10^9 o Molality (m) M = moles of solute/ kg of solvent Example: 10 grams C6H12O6 and 100 grams of water. Calculate molality, %mass, and x %mass = 10g/110g x 100 Molality (m)= moles solute/kg solvent = (10.0 g glucose x 1mol/180.16g)/0.100kg water = .555 m X glucose = (10 grams glucose x 1mol/180.16 g)/10.0g glucose x 1mol/180.16g +100g water x 1mol/ 18.015 = 9.90 x 10^-3...
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