Chemistry lecture 1

Chemistry lecture 1 - equilibrium with dissolved solute-A...

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Sakai - Syllabus - General Information File - Forms - Lecture Notes - Announcement - Old Exams - Grades - Chatroom Assessments - 3 quizzes 5% - 3 worksheets 5% Online Hw - Weekly Assignments 10% - LearnSmart 5% Exams 3 midterms 15% each Final Exam 30% Physical Properties of Solution - A solution is a homogeneous mixture of two or more substances. - A Solution consists of a solvent and one or more solutes. Solute Solvent Example Gas Gas Air Gas Liquid Soda (CO2 in water) Gas Solid H2 gas in Pd Catalytic Converter (CO in Pt) Liquid Liquid Alcoholic Drinks (Ethanol in water) Liquid Solid (Dental Amalgams Hg in Ag) Solid Liquid sea water Solid Solid Brass (Zn in Cu) Steel (C in Fe) White Gold (Ag/Cu Solutions - The solubility of a solute is the maximum amount that dissolves in a fixed quantity of solvent at a given temperature o an unsaturated solution is one that contains less solute than the solvent has the capacity to dissolve at a specific temperature o A saturated solution is one that contains the maximum amount of solute that will dissolve in a solvent at a specific temperature. Undissolved solute is in dynamic
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Unformatted text preview: equilibrium with dissolved solute-A supersaturated solution contains more than the equilibrium concentration of a solute-Supersaturated solutions are unstable Concentration Units-The amount of solute relative to the volume of a solution or the amount of solvent in a solution is called concentration o Molarity M = moles of solutes/liters of solution o Mole fraction X o Parts per million ppm(suba) = mass of A/ mass of solution x 10^6 o Parts per billion ppb(suba) = mass of A/mass of solution x 10^9 o Molality (m) M = moles of solute/ kg of solvent Example: 10 grams C6H12O6 and 100 grams of water. Calculate molality, %mass, and x %mass = 10g/110g x 100 Molality (m)= moles solute/kg solvent = (10.0 g glucose x 1mol/180.16g)/0.100kg water = .555 m X glucose = (10 grams glucose x 1mol/180.16 g)/10.0g glucose x 1mol/180.16g +100g water x 1mol/ 18.015 = 9.90 x 10^-3...
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This note was uploaded on 02/19/2012 for the course CHEM 162 taught by Professor Goodfella during the Spring '12 term at Dartmouth.

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Chemistry lecture 1 - equilibrium with dissolved solute-A...

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