Exam 2 2011

Exam 2 2011 - Name: _ Student ID:_ Page 1 Zoology 470 -...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Name: ______________________________________ Student ID:________________________ Page 1 Zoology 470 - Exam #2 – 2011 This exam has 6 pages and a total of 50 points . You will have 90 minutes to complete it. Answer all short answer questions as briefly as possible. Make sure your name and ID number are on all pages. 1. Provide concise definitions for each of the following ( 6 points ) a. Müllerian duct: b. blastocoel: c. involution: . d. maskin: e. myogenic factor: f. homeotic gene: 2. Complete the following table referring to cleavage patterns in early embryos of various animals ( 5 points ) Animal Yolk Distribution Completeness of Cleavage Orientation of cleavages Drosophila (fruit fly) Not applicable Monkey (mammal) rotational Starfish (an echinoderm) holoblastic Chicken (bird) Snail (a gastropod mollusk)
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Name: ______________________________________ Student ID:________________________ Page 2 3. Circle true (T) or false (F) for each of the following ( 7 points ) T F Humans, like other chordates, are deuterostomes T F A weak mutation in the mouse pax-6 gene would be expected to result in loss of posterior structures, since the fly homologue is involved in patterning posterior segments of the embryo T F The Wolffian duct is normally retained in male mammals T F Proteins can act as transcriptional regulators or translational regulators, but not both T F Germ band extension in Drosophila occurs via convergent extension T F Primordial germ cell migration in vertebrates would be expected to be normal when excess SDF-1 is added T F Enhancers are proteins that can act 5' ("upstream") or 3' ("downstream") to their associated gene T F Alternative splicing leads to the production of genes with slightly different coding regions, leading to proteins with slightly different amino acid sequence T F If the poly A tail of a mRNA were removed, the stability of that mRNA would be expected to decrease T F If the bicoid RNA is engineered such that it is missing most of its 3'-UTR, it would be expected to localize normally in the oocyte T F Nodal proteins, which encode key transcription factors, act to pattern the dorsoventral axis of sea urchin embryos T F In a species of frog in which there is 500 times the amount of yolk as in Xenopus , cleavage would be expected to be Holoblastic T F A microRNA (miRNA) that is an exact match to a sequence in the 3’-untralated region (3’-UTR) of a mRNA will tend to block translation of that mRNA, but will not affect its stability T F Unlike the gap genes, not all segment polarity genes encode transcription factors 4. Match the following cell types from various gastrula-stage embryos from the left column to the
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 6

Exam 2 2011 - Name: _ Student ID:_ Page 1 Zoology 470 -...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online