HmwkQs19to26 - Homework 19 Question If the odds are 18 to 5 against success then the probability of success is Answer 5/23 = 21.74 5/18 = 27.78

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Homework 19 Question If the odds are 18 to 5 against success, then the probability of success is: Answer 5/23 = 21.74% 5/18 = 27.78% 5/13 = 38.46% 13/18 = 72.22% 18/23 = 78.26% Question A six sided die (like with a Monopoly or Yahtzee game) is put into a microwave on low power in hopes of making it no longer be fair. The chances of each side are now: P(1)=0.1 P(2)=0.15 P(3)=0.15 P(4)=0.15 P(5)=0.15 P(6)=? What is the probability of a 6? Answer 0.05 0.10 0.20 0.25 0.30 Question Which of the following is a valid probability model? Answer P(A)=0.6 P(B)=0.5 P(C)=-0.1 P(A)=1.0 P(B)=0.0 P(C)=0.0 P(A)=0.3 P(B)=0.3 P(C)=0.3 P(A)=0.25 P(B)=0.25 P(C)=0.6
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Homework 20 Question 70% of students in a class are from in-state. 60% of students in a class are female. 45% of the students are in-state females. What percent of students are from out-of-state? Answer 15% 30% 35% 42% 85% Question What percent are either in-state or female (or both)? Answer 15% 30% 35% 42% 85% Question What percent are out-of-state females? Answer 15% 30% 35% 42% 85%
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Question A dart player has a 30% chance of getting a bull's-eye on the first throw. If the first throw is a bull's-eye they have a 45% chance of getting one on the second throw. If the first throw didn't hit the bull's-eye they have a 15% chance of getting one on the second throw. What is the probability of getting at least one bull's eye? Answer 0.27 = 27% 0.4 = 40% 0.405 = 40.5% 0.595 = 59.5% 0.6 = 60% 0.73 = 73% Question What is P(missing bull's-eye on second | hit bull's-eye on first) ? Answer 0.15 = 15% 0.165 = 16.5% 0.3 = 30% 0.45 = 45% 0.55 = 55% 0.85 = 85% Question A dart player has a 30% chance of getting a bull's-eye on the first throw. If the first throw is a bull's-eye they have a 45% chance of getting one on the second throw. If the first throw didn't hit the bull's-eye they have a ____% chance of getting one on the second throw. If the second throw is independent of the result of the first throw, what value would have to go where the blank is? Answer
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This note was uploaded on 02/22/2012 for the course STAT 110 taught by Professor Johnson during the Fall '07 term at South Carolina.

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HmwkQs19to26 - Homework 19 Question If the odds are 18 to 5 against success then the probability of success is Answer 5/23 = 21.74 5/18 = 27.78

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