University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.62: a) Using the same algebra as in Problem 3.58(a), m/s 8 13 0 . v = . b) Again, the algebra is the same as that used in Problem 3.58; m/s 4 8 . v = , at an angle of ° 1 . 9 , this time above the horizontal. c) The graph of ) ( t v x is a horizontal line. A graph of ) ( t y vs. ) ( t x shows the trajectory of Mary Belle as viewed from the side:
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Unformatted text preview: d) In this situation it’s convenient to use Eq. (3.27), which becomes 2 1 ) m 071115 . ( ) 327 . 1 ( x x y--= . Use of the quadratic formula gives m 8 . 23 = x ....
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