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3.62:
a) Using the same algebra as in Problem 3.58(a),
m/s
8
13
0
.
v
=
.
b) Again, the algebra is the same as that used in Problem 3.58;
m/s
4
8
.
v
=
, at an angle
of
°
1
.
9
, this time above the horizontal.
c) The graph of
)
(
t
v
x
is a horizontal line.
A graph of
)
(
t
y
vs.
)
(
t
x
shows the trajectory of Mary Belle as viewed from the side:

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**Unformatted text preview: **d) In this situation it’s convenient to use Eq. (3.27), which becomes 2 1 ) m 071115 . ( ) 327 . 1 ( x x y--= . Use of the quadratic formula gives m 8 . 23 = x ....

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