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HW+2+solutions

# HW+2+solutions - HW 2 solutions 1 At high temperatures...

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HW 2 solutions 1. At high temperatures phosphine (PH 3 ) dissociates into phosphorus and hydrogen by the following reaction: 2 4 3 6 4 H P PH + At 800 the rate at which phosphine dissociates is 3 3 6 10 715 . 3 PH PH C dt dC - × - = for t in seconds. The reaction occurs in a constant-volume, 2-L vessel, and the initial concentration of phosphine is 5 kmol/m 3 . (a). If 3 mol of the phosphine reacts, how much phosphorus and hydrogen is produced? (b). Develop expressions for the number of moles of phosphine, phosphorus, and hydrogen present at any time, and determine how long it would take for 3 mol of phosphine to have reacted. (b) 4PH 3 P 4 +6H 2 (c) Assume that 4X mol of PH 3 reacts at time t, X mol of P 4 and 6X mol of H 2 is produced, respectively. 4X=3mol => X=0.75 mol N P4 =X=0.75 mol N H2 =6X=4.5 mol (d) Initial molar number of PH 3 : mol m m mol L m kmol V C N PH PH 10 1000 2 * 5000 2 * 5 * 3 3 3 3 3 = = = = Assume that 4X mol of PH 3 reacts at time t. 10-4X mol of PH 3 is left, and X mol of P 4 and 6X mol of H 2 is produced, respectively.

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