{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

s11q8Key - Chem 171 Quiz 8 Version A 1 A triprotic acid(H 3...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Chem 171 Quiz 8 Version A 1. A triprotic acid (H 3 A) of mass 0.5740 g was dissolved in water. It required 34.65 mL of a 0.550 M KOH (aq) solution for neutralization. What is the equivalent mass of the acid? Write the molecular eq. Show the phases. H 3 A (aq) + 3 KOH (aq) Æ K 3 A(aq) + 3H 2 O(l) 0.03465 L x 0.550 mol KOH / L = 0.01906 mol KOH 0.01906 mol KOH = 0.01906 equiv of acid 0.5740 g / 0.01906 equiv acid = 30.1 g / mol 2. Write the molecular equation, total ionic, and net ionic equation for the neutralization of magnesium hydroxide, a typical hydroxide used in antacids. Show phases. Identify the spectator ion/s. Mg(OH) 2 (s) + 2 HCl (aq) Æ MgCl 2 (aq) + 2 H 2 O (l) Mg(OH) 2 (s) + 2 H + (aq) + 2 Cl - (aq) Æ Mg 2+ (aq) + 2 Cl- (aq) + 2 H 2 O (l) Mg(OH) 2 (s) + 2 H + (aq) Æ Mg 2+ (aq) + 2 H 2 O (l) Cl- (aq) is a spectator ion Chem 171 Quiz 8 Version B 1. How many equivalents of sulfuric acid will be needed to neutralize 25.00 mL of 0.0345 M aluminum hydroxide solution? Write the molecular equation. Show the phases....
View Full Document

{[ snackBarMessage ]}

Page1 / 2

s11q8Key - Chem 171 Quiz 8 Version A 1 A triprotic acid(H 3...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon bookmark
Ask a homework question - tutors are online