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Unformatted text preview: pan (zp695) Ch14h2 chiu (56565) 1 This printout should have 25 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points A particle with charge +6 nC (a nanocoulomb is 1 10 9 C) is located at the origin. At a point P given by r = . 5 m , , , the electric field will be of the form E = E x , , . Find E x . Correct answer: 215 . 701 N / C. Explanation: The general equation for the electric field at P is E = 1 4 q  r  2 r. The x component would be given by E x = 1 4 q  r  2 r x . We have the various quantities that we need: q = 6 nC = 6 10 9 C  r  = 0 . 5 m r x = 1 . Plugging in, we obtain E x = 1 4 6 10 9 C (0 . 5 m) 2 = 215 . 701 N / C . 002 (part 1 of 2) 10.0 points You want to create an electric field E = , 4179 N / C , at the origin. Find the y coordinate where you would need to place a proton, in order to create this field at the origin. Correct answer: 5 . 86603 10 7 m. Explanation: The equation for the electric field, in gen eral, is E = 1 4 q  r  2 r. In this case, q = 1 . 6 10 19 C for a proton, and r = , 1 , , since the field points in the positive y direc tion.  r  is the unknown we want to solve for. We can write E y = 4179 N / C = 1 4 1 . 6 10 19 C  r  2  r  2 = 1 4 1 . 6 10 19 C 4179 N / C  r  = 1 4 1 . 6 10 19 C 4179 N / C = 5 . 86603 10 7 m . We choose the minus sign to place the pro ton below the origin; this way the field will point upward like we want it to. 003 (part 2 of 2) 10.0 points Instead of a proton, where would you place an electron to produce the same field at the origin? Correct answer: 5 . 86603 10 7 m. Explanation: This is simple. The proton and electron carry the same magnitude of charge, but the electrons charge is negative. The calculation from above will be exactly the same, but we choose a positive sign at the end to place the electron above the origin. This way the field will still point upward as we want it to. pan (zp695) Ch14h2 chiu (56565) 2 004 (part 1 of 6) 10.0 points A  (piminus) particle, which has charge e , is at location r = 9 10 9 , 2 10 9 , 5 10 9 m . You will find the components of the electric field at another point P given by r P = 7 10 9 , 4 10 9 , 4 10 9 m due to the  particle. Begin by finding the x component of the field, which we will call E x ( P ). Answer in N/C. Correct answer: 3 . 19388 10 6 N / C. Explanation: Lets write the general expression for the electric field at P due to the  as E P = 1 4 Q   r P  2 r P . Therefore in order to determine the com ponents of the field, we need to find the unit vector r P pointing from the location of the  to the point P and the distance between those two locations, r P ....
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This note was uploaded on 02/21/2012 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas.
 Spring '08
 Turner

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