CollisionTheory

CollisionTheory - A       N A V reaction...

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Colby College Collision Theory A + B products N A and N B molecules in a container of volume V gives: number densities of molecules: ρ A = N A /V and ρ B = N B /V hard core collision cross section: σ = π (r A + r B ) 2 = π d 2 d is the collision diameter molecule A moving, all others fixed: in time t, A sweeps out volume = σ c t number of molecules inside this volume = σ c t N B /V collision frequency = number of collisions per unit time = σ c N B /V total collisions = N A σ c N B /V total collisions per unit volume: = σ c ( N A /V)( N B /V) = σ c ρ A ρ B B molecules are moving: z AB = σ c rel ( N A /V)( N B /V) collisions per unit volume per unit time: z AB = σ 8kT πμ ½ N A V N B V with μ = m A m B m A + m B reaction rate: d( N A /V) dt = z AB = σ c rel N A V N B V [A] = 1 N
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Unformatted text preview: A       N A V reaction rate: – d( N A /N A V) dt = z AB = σ c – rel N A       N A N A V       N B N A V – d[A] dt = z AB = σ c – rel N A [A] [B] – d[A] dt = k 2 [A] [B] k 2 = σ c – rel N A = σ       8kT πμ ½ N A = π d 2       8kT πμ ½ (1000 L/m 3 ) N A H 2 + I 2 → 2 HI r H 2 = 1.1 Å r I 2 = 1.7 Å σ = 0.246 nm 2 c – rel = 2060 m s-1 k 2 = π (1.1x10-10 +1.7x10-10 m) 2       8(1.381x10-23 J K-1 )(400 K) π 3.33x10-27 kg ½ (1000 L/m 3 ) 6.022x10 23 mol-1 = 3.1x10 11 L mol-1 s-1 A • B • B • r B r A d B B B c – ∆ t Area = π d 2 d A B...
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This document was uploaded on 02/22/2012.

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