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# novproblem_pdf - cannon(kgc299 HW14 berg(54595 This...

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cannon (kgc299) – HW14 – berg – (54595) 1 This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points Find all functions g such that g ( x ) = 3 x 2 + 5 x + 4 x . 1. g ( x ) = x ( 3 x 2 + 5 x + 4 ) + C 2. g ( x ) = 2 x ( 3 x 2 + 5 x + 4 ) + C 3. g ( x ) = 2 x parenleftbigg 3 5 x 2 + 5 3 x - 4 parenrightbigg + C 4. g ( x ) = x parenleftbigg 3 5 x 2 + 5 3 x + 4 parenrightbigg + C 5. g ( x ) = 2 x ( 3 x 2 + 5 x - 4 ) + C 6. g ( x ) = 2 x parenleftbigg 3 5 x 2 + 5 3 x + 4 parenrightbigg + C 002 10.0points Find the value of f (0) when f ′′ ( t ) = 4(3 t + 2) and f (1) = 3 , f (1) = 6 . 1. f (0) = 11 2. f (0) = 10 3. f (0) = 12 4. f (0) = 9 5. f (0) = 8 003 10.0points Find the value of f ( π ) when f ( t ) = 4 3 cos 1 3 t - 4 sin 2 3 t and f ( π 2 ) = 9. 1. f ( π ) = 1 + 3 3 2. f ( π ) = - 1 - 2 3 3. f ( π ) = 2 + 3 3 4. f ( π ) = 1 + 2 3 5. f ( π ) = - 2 - 2 3 6. f ( π ) = - 2 - 3 3 004 10.0points Find f ( x ) on ( - π 2 , π 2 ) when f ( x ) = 5 + 2 tan 2 x and f (0) = 5. 1. f ( x ) = 3 + 5 x + 2 sec x 2. f ( x ) = 5 + 3 x + 2 tan x 3. f ( x ) = 5 - 3 x - 2 tan x 4. f ( x ) = 3 + 5 x + 2 sec 2 x 5. f ( x ) = 7 - 3 x - 2 sec x 6. f ( x ) = 5 + 3 x + 2 tan 2 x 005 10.0points Find the unique anti-derivative F of f ( x ) = 2 e 4 x + 4 e 2 x + 3 e 2 x e 2 x for which F (0) = 0.

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cannon (kgc299) – HW14 – berg – (54595) 2 1. F ( x ) = e 2 x + 4 x - 3 4 e 4 x - 1 4 2. F ( x ) = e 2 x - 4 x + 3 4 e 4 x + 7 4 3. F ( x ) = e 2 x - 4 x + 3 4 e 2 x + 1 4 4. F ( x ) = 1 2 e 4 x + 4 x - 3 4 e 4 x - 1 4 5. F ( x ) = e 2 x + 4 x - e 2 x 6. F ( x ) = 1 2 e 4 x - 4 x + e 2 x - 1 4 006 10.0points Find f ( x ) when f ( x ) = 3 cos x - 2 sin x and f (0) = 8. 1. f ( x ) = 3 sin x + 2 cos x + 6 2. f ( x ) = 3 cos x + 2 sin x + 11 3. f ( x ) = 3 cos x + 2 sin x + 5 4. f ( x ) = - 3 cos x + 2 sin x + 11 5. f ( x ) = 3 sin x + 2 cos x + 5 6. f ( x ) = - 3 sin x + 2 cos x + 6 007 10.0points Find the value of f (0) when f ( x ) = 2 e 2 x , f (ln2) = 8 .
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