Unformatted text preview: n = 1000 the zscore for a 95% CI is 1.96 the 95% CI is 0.41 ± 1.96 * sqrt( 0.41 * (10.41) / 1000 ) (0.3795159 , 0.4404841) b) about 38% is a good estimate for the minimum proportion of first  year defaults that were approved on the basis of falsified applications....
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 Spring '11
 SMITH
 Normal Distribution, 38%, sample confidence intervals, Phat

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