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Unformatted text preview: n = 1000 the z-score for a 95% CI is 1.96 the 95% CI is 0.41 1.96 * sqrt( 0.41 * (1-0.41) / 1000 ) (0.3795159 , 0.4404841) b) about 38% is a good estimate for the minimum proportion of first - year defaults that were approved on the basis of falsified applications....
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This note was uploaded on 02/24/2012 for the course ECON 101 taught by Professor Smith during the Spring '11 term at University of Phoenix.
- Spring '11