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mostowfi (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 This print-out should have 55 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points What would equal 5 meters? 1. 50 dm correct 2. 50 dam 3. 50 mm 4. 50 cm 5. 0.5 km 6. 0.5 hm Explanation: (50 dm) 1 m 10 dm = 5 m 002 10.0 points What unit of measure would you use for mass? 1. None of these 2. liters 3. cubic centimeters 4. grams correct Explanation: Liters and cubic centimeters are units of measure for volume. 003 (part 1 of 5) 10.0 points s is a distance with unit [L], t is a time with unit [T] and is an angle in radians. Find the dimension for the quantity c 1 in the expression s = c 1 t . 1. 1/[L] 2. None of these 3. [T] 2 /[L] 4. [T] 5. 1/[T] 6. [L]/[T] 2 7. 1/[T] 2 8. [T]/[L] 9. [L] 10. [L]/[T] correct Explanation: s = c 1 t c 1 = s t [ c 1 ] = [ s ] [ t ] = [L] / [T] 004 (part 2 of 5) 10.0 points Find the dimension for the quantity c 2 in the expression s = c 2 t 2 . 1. [T] 2. 1/[T] 3. [T] 2 /[L] 4. [L] 5. [L]/[T] 6. 1/[L] 7. [L]/[T] 2 correct 8. 1/[T] 2 9. None of these 10. [T]/[L] Explanation: mostowfi (nm22898) Assignment # 1 - Introductory Physics and 1D Kinematics schultz (WVFAL20 c 2 = s t 2 [ c 2 ] = [ s ] [ t ] 2 = [L] / [T] 2 005 (part 3 of 5) 10.0 points WITHDRAWN 006 (part 4 of 5) 10.0 points WITHDRAWN 007 (part 5 of 5) 10.0 points WITHDRAWN 008 10.0 points How many (whole number of) 90 kg people can safely occupy an elevator that can hold a maximum mass of exactly 1 metric ton? A metric ton is 1 . 000 10 3 kg. Correct answer: 11 people. Explanation: Let : 1 ton = 1 . 000 10 3 kg and R = 90 kg / person . Using dimensional analysis, n = ( 1 . 000 10 3 kg ) 1 person 90 kg = 11 . 1111 persons Note that the numerical answer 11 . 1111 must be rounded down to 11 people because of overload considerations. 009 10.0 points What is equivalent to a cubic centimeter? 1. centiliter 2. milliliter correct 3. liter 4. deciliter Explanation: 1 mL = 1 cc. 010 10.0 points An electron travels 1 . 37 m in 5 . 89 10- 8 s. How fast is it traveling? Correct answer: 2 . 32598 10 7 m / s. Explanation: Let : s = 1 . 37 m and t = 5 . 89 10- 8 s . v = s t = 1 . 37 m 5 . 89 10- 8 s = 2 . 32598 10 7 m / s . 011 10.0 points Convert an acceleration of 5 . 7 mi / h / s to m / s 2 . Correct answer: 2 . 54758 m / s 2 . Explanation: Let : a = 5 . 7 mi / h / s . a = 5 . 7 mi h s 1 . 609 km 1 mi 1000 m 1 km 1 h 3600 s = 2 . 54758 m / s 2 . 012 10.0 points Convert 47 . 7 mi / h to m/s. 1 mi = 1609 m. Correct answer: 21 . 3193 m / s. Explanation: 1 mi = 1609 m 1 h = 3600 s (47 . 7 mi / h) 1609 m 1 mi 1 h 3600 s = 21 . 3193 m / s .... View Full Document
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