Quiz1SolnPC - J = 1 kg m 2 /s 2 , and that 1 kPa = 1 kJ/m 3...

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------------------ Name: DivisiQn: _____ _ Quiz #1 ME 200 Prof. Lucht 20 Jan 2012 A gas is compressed from an initial volume 171 = 0.42m 3 to a final volume of tr2 = 0.12 m 3 During this quasi-equilibrium compression process, the pressure changes according to p = a t7'+b, where a = -1200 kPalm 3 and b = 600 kPa. Compute the work during this process. Is the work positive or negfltive? Follow the solution procedure we have discussed. List Given, Find, Assumptions, Diagram and System Identification, Basic Equations, Solution, and Solution Check. 2 0 P 0 Note that 1
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Unformatted text preview: J = 1 kg m 2 /s 2 , and that 1 kPa = 1 kJ/m 3 .~ ~. J1 t 5 G: v-e VI ':-j tl ~ cO 0'1.1 PdS ~,' 0"" pro ct't :5 ~) V, = C), 4 2m '3 \:1'2-= a, /2 rn B p -::: cdl + Ie> ot ~ -1'2-0 0 ;.,;~ b = i toO () !J)c., .:s y si eA1A " p::::4 Vt-Io ------. ....;;;> @) ----------------------------1 S D llA--lzO YJ : \JIJr> -= 5,2 r oHT~ Sz(~ b"+~) J If @ = ~ a (V2-L-tf,~) +, b (vz--~) J -:= ~ (-tWO ~:r:)( {6./ I 2 Wl'3)'2-{O,lflIt15~ . I ~ -l-(& 0 0 l~ ') ( 01, J 2.--~ If L fI'I 3 ) I -::= +-1.7. 2 (LT-l'Sf ~J Wp -::= -<62.<6' k-T...
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This note was uploaded on 02/22/2012 for the course ME 200 taught by Professor Gal during the Spring '08 term at Purdue University-West Lafayette.

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Quiz1SolnPC - J = 1 kg m 2 /s 2 , and that 1 kPa = 1 kJ/m 3...

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