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Unformatted text preview: theta 7 (vector BD) = 80.7566 degrees theta 4 (vector ED) = 174.237 degrees Follower angular velocity = 4.35 rad/sec (hence CCW) Roller angular velocity = 83.76 rad/ sec (hence 83.76 rad/sec CW) 2) dR 4 /dt = 12.25 ft/sec d(theta4)/dt = 41.39 rad/sec Homework No. 4 1) Problem 3.29 on p. 162 of the text Follower angular velocity = 4.38 rad/sec (hence CCW) Roller angular velocity = 83.0 rad/ sec (hence 83.0 rad/sec CW) 2) Link 4 angular velocity = 6.56 rad/sec (hence CCW) I 25 is located 2.55 inches to the left of point O 2 along the line O 2 O 4 Using the input angular velocity and the distance I12toI25 yields: Block 5 velocity = 25.5 in/sec upwards...
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This note was uploaded on 02/22/2012 for the course ME 352 taught by Professor Staff during the Spring '08 term at Purdue UniversityWest Lafayette.
 Spring '08
 Staff

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