me352_homework1-4solutions

me352_homework1-4solutions - theta 7 (vector BD) = 80.7566...

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ME 352 Spring 2012 Homework Answers Homework No. 1 1) Problem 1.5 on p. 41 of the text a) M=1 b) M=1 c) M=0 (exception since mobility is one) d) M=1 2) Problem 1.11 on p. 42 of the text M=1 (wheel rolling without slip) M=2 (wheel slipping) 3) Phi = 30 degrees. There are an infinite number of solutions, hence review the procedure in Chapter 1 of the text. 4) Phi = 20 degrees. There are an infinite number of solutions, hence review the procedure in Chapter 1 of the text. Homework No. 2 Configuration #1: theta3 = 11.578 degrees theta4 = 325.312 degrees Configuration #2: theta3 = 82.048 degrees theta4 = 128.315 degrees Homework No. 3 1) Problem 3.29 on p. 162 of the text Position Solution:
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Unformatted text preview: theta 7 (vector BD) = 80.7566 degrees theta 4 (vector ED) = 174.237 degrees Follower angular velocity = 4.35 rad/sec (hence CCW) Roller angular velocity = -83.76 rad/ sec (hence 83.76 rad/sec CW) 2) dR 4 /dt = 12.25 ft/sec d(theta4)/dt = -41.39 rad/sec Homework No. 4 1) Problem 3.29 on p. 162 of the text Follower angular velocity = 4.38 rad/sec (hence CCW) Roller angular velocity = -83.0 rad/ sec (hence 83.0 rad/sec CW) 2) Link 4 angular velocity = 6.56 rad/sec (hence CCW) I 25 is located 2.55 inches to the left of point O 2 along the line O 2 O 4 Using the input angular velocity and the distance I12-to-I25 yields: Block 5 velocity = 25.5 in/sec upwards...
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This note was uploaded on 02/22/2012 for the course ME 352 taught by Professor Staff during the Spring '08 term at Purdue University-West Lafayette.

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