problem03_71

University Physics with Modern Physics with Mastering Physics (11th Edition)

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3.71: a) The height above the player’s hand will be m 40 . 0 2 sin 2 0 2 2 0 2 0 = = g v g v y α , so the maximum height above the floor is 2.23 m. b) Use of the result of Problem 3.59 gives 3.84 m. c) The algebra is the same as that for Problems 3.58 and 3.62. The distance y is m 1.22 m 83 . 1 m 05 . 3 = - , and m/s. 65 . 8 m) 22 . 1 35 tan m) 21 . 4 (( 35 cos 2 m) 21 . 4 ( ) m/s 80 . 9 ( 2 2 2 0 = - ° ° = v d) As in part (a), but with the larger speed, m. 09 . 3 ) m/s 80 . 9 (
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