Unformatted text preview: compensate for springback is to overbend the part (i.e., bend the sheet more than you want, hoping that it will spring back to the desired shape). Consider the bending of an aluminum sheet (Al 1200-O) with Y=5075 psi, E=10 6 psi, and T=1/8 in. a) Which case will result in more springback: R i = 1 in or R i = 2 in? Why? b) You are given a sketch of the setup for bending operation as shown in Figure 2. The target angle for the bend is 90° and R i = 2 in. The process engineers aren´t certain how much of an angle to specify for the initial bend. After assuming that the length of the bent region of the sheet, s, stays constant and doing some geometry, they used Eq. 1 to find that the difference between the initial and final bend angles will be approximately 2°. What value θ ? should they specify for Figure 1: schematic of springback bending Figure 2: sketch of V-die bending...
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- Spring '04
- 2°, 90°, Bend radius, final bend