MIT2_019S11_MD3 - 2.019 Desi 2 019 D ign of O f Ocean...

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2.019 Design of Ocean Systems ecture Lecture 4 14 Mooring Dynamics (III) April 1, 2011
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Cable Load-Excursion Relation X = l l s + x ³ ´ X = l h ¡ 1+2 T H ¢ 2 1 + T H cosh 1 1+ wh w T H Restoring Coefficient: " # ³ ´ C 11 = d T H = w ¡ 2 ¢ 1 / 2 +cosh 1 d X T H T H 1+2 wh ϕ W l l s h x X Anchor Vessel Moored with One Anchor Line X(m) T H (k N) Image by MIT OpenCourseWare. Image by MIT OpenCourseWare.
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T Z T A B T H x h L l l s Horizontal Tension, kN T H 1000 500 0 +50m +50m 2 δ * Line A Line B Fm = 660 kN 2 δ = T HA _ T HB kN m δ Displacement Image by MIT OpenCourseWare. Image by MIT OpenCourseWare. Image by MIT OpenCourseWare.
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= ³ ´ Catenary Solution ⎯⎯ Key Results (with Elasticity) • Horizontal force for a given fairlead tension T: q ¡ ¢ 2 AE T 2 wh T H + 1 AE AE AE • Minimum line length required (or suspended length for a given fairlead tension) for gravity anchor: p l min = 1 T 2 T 2 w H ertical force at the fairlead: Vertical force at the fairlead: T z = wl min orizontal scope (length in plan view from fairlead to touchdown point): Horizontal scope (length in plan view from fairlead to touchdown point): x = T H sinh 1 min + T H l min w T AE H AE : stiffness of the cable
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Analysis of Spread Mooring System • Mean position of the body is determined by balancing force/moment between ose due to environments and mooring those due to environments and mooring lines • Iterative solver is usually applied (x i , y i ) T Hi y x ψ i Total mooring line force/moment: F = n M 1 T H i cos y i i = 1 n F M 2 = T H i sin i i = 1 n F M 6 = T H i [ x i sin i - y i cos i ] i = 1 Total mooring line restoring coefficients: C 11 = n k i cos 2 i i = 1 n Ck i in 2 22 = s i i = 1 C 66
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This note was uploaded on 02/24/2012 for the course MECHANICAL 2.019 taught by Professor Yumingliu during the Spring '11 term at MIT.

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MIT2_019S11_MD3 - 2.019 Desi 2 019 D ign of O f Ocean...

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