MIT2_092F09_lec21 - 2.092/2.093 Finite Element Analysis of...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
2.092/2.093 Finite Element Analysis of Solids & Fluids I Fall ‘09 Lecture 21 - Solution of the Generalized Eigenvalue Problem Prof. K. J. Bathe MIT OpenCourseWare Reading assignment: Chapters 10 and 11 MU ¨ + KU = R (1) Aside: M could have zero masses. Then we use Gauss elimination on K to remove zero-mass DOFs, but we denote the final matrix still as K . Then, in free vibrations: MU ¨ + KU = 0 (2) where now M and K are assumed to be positive definite matrices, i.e. U ˜ T MU ˜ > 0, U ˜ T KU ˜ > 0 for any U ˜ = 0. Then, we obtain the eigenvalue problem = λ i = λ i i (A) where 0 < λ 1 λ 2 . . . λ n . ���� ���� ���� φ 1 φ 2 φ n Recall: φ T i j = δ ij φ T i j = ω i 2 δ ij = λ i δ ij The Case of Multiple Eigenvalues Assume λ 1 = λ 2 < λ 3 , i.e. λ 1 has a multiplicity of 2 ( m = 2), φ 1 and φ 2 are two eigenvectors for λ 1 and λ 2 , and φ 1 = φ 2 . Then, we have K α φ 1 = λ 1 M α φ 1 ( α : any constant) (3) K β φ 2 = λ 1 M β φ 2 ( β : any constant) (4) Hence, K ( α φ 1 + β φ 2 ) = λ 1 M ( α φ 1 + β φ 2 ) (5) Eq. (5) shows α φ 1 + β φ 2 = φ ˜ is also an eigenvector corresponding to λ 1 ! We can change the
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern