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11rankine_regen

# 11rankine_regen - comparison of rankine with single...

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comparison of rankine with single regeneration kPa := 10 3 Pa MPa := 10 6 Pa basic reference problem ... 3 kJ := 10 3 J bar := 0.1MPa Rankine_class_example.mcd kN := 10 N state 1: condenser outlet same as reference 3 Table 1 or Table A.1.1 T 1 := 40 p 1 := 7.384kPa v f_1 := 0.0010078 m v 1 := v f_1 kg kJ kJ kJ kJ s f_1 := 0.5725 kg K s 1 := s f_1 s fg_1 := 7.6845 kg K h f_1 := 167.57 kg h fg_1 := 2406.7 kg h 1 := h f_1 state 2: pump outlet assume v f = v 1 constant, isentropic, ds = 0 =>T*ds= 0 => h2 = h1+v1*dp from relationships Tds = dh + v*dp integrated with constant v and Tds = 0 p 2 := 30bar s 2 := s 1 := + = 170.586 kJ h 2 h 1 v 1 ( p 2 p 1 ) h 2 kg kJ kJ w p := h 1 h 2 using C Cp := 4.184 actual units kg kg K p w p = − 3.016 kJ and ... eqn 5.18 h 2 h 1 = Cp ( T 2 T 1 ) T 2 := T 1 + h 2 h 1 T 2 = 40.721 kg Cp state 3: boiler outlet p 3 := p 2 T 3 := 460 p 3 = 3 MPa interpolation kJ kJ from interpolation Table A.1.3 P=3MPa page 622 h 3 = 3366.5 s 3 = 7.113 kg kg K state 4: turbine outlet isentropic expansion to 40 deg C s 4 := s 3 determine h 4 from x s 4 s f_1 s 4 = s f_1 + x s fg_1 => x := x = 0.851 s fg_1 kJ kJ h 4 := h f_1 + h fg_1 x h 4 = 2216 w t := h 3 h 4 w t = 1150 kg kg thermal efficiency work_net Q H + Q L w t + w p ( h 3 h 4 ) + ( h 1 h 2 ) = = = = η th Q H Q H Q H h 3 h 2 + w ( h 3 h 4 ) ( h 2 h 1 ) w t p η th := h 3 h 2 η th = 0.359 th η := h 3 h 2 η th = 0.359 Q H := h 3 h 2 Q L := h 1 h 4 Q H + Q L η th_1 := Q H η th_1 = 0.359 10/17/2005 1

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same cycle with regeneration extract steam at 400kPa (4 bar) from turbine to mix
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