# ps5_soln - 2.611 Fall 2006 Problem Set#5 Answer Key Problem...

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2.611 Fall 2006 Problem Set #5 Answer Key Problem 1 (Just parts A and B).

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Problem 2 Diesel engine (two stroke) 3 1 1.0 Vm = , 13.0 v r = , 1.8 p r = , 1.4 c r = , 1 300 o TK = , () 2 1 1 bar 100 / p kN m = , / 1.00/ 0.7143 pv CC γ = = , 0.286 / R kJ kgK = , 79 rpm Temperature: 1 0.4 1 21 2 300 13 836.9 o V TT x K V ⎛⎞ == = ⎜⎟ ⎝⎠ 32 836.9 1.8 1506 o p x r x K =

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43 1506.5 1.4 2109.1 o c TT x r x K == = () 0.4 544 5 1.4 / 2109.1 864.9 13.0 o x V V K ⎛⎞ = ⎜⎟ ⎝⎠ ( ) 13 2 Hv Qm C T T =− , where 11 1 / 100 1/ .286 300 mp VR T x x b. 1.1655 mk g = c . 1 1.1655 1506.5 836.9 557.4 1.4 HI Qx k J = ( ) ( ) 24 3 1.1655 1.0 2109.1 1506.5 702.3 Hp C T T x k J = = 25 1 1 1.1655 864.9 300 470.29 1.4 L C T T x k J d. Work output = 2 557.4 702.3 470.29 789.45 HI H L QQ Q k J +− = + = ±± ± per cycle Power of the two stroke engine = Work / 60 1.039.4 / xrpm kW cycle = e. The turbocharger compressor pressure ratio / 3.9 out in pp = , 0.83 pc η = 1 / / 3.9 1.5976 pc out in out in p p γ ηγ = 300 1.5976 479.3 out comp x = 1 1 1 1 479.3 479.3 300 comp comp w T ε −− ( ) 1 1 479.3 0.8 479.3 300 335.8 o TK = f. All temperatures are scaled from previous results by 335.8/300 1.1195 = 1 2 936.97 o = 1 3 1686.6 o = 1 4 2361.2 o = 1 5 968.3 o =
Heat transfers 1 H Q , 2 H Q , and L Q are all scaled by mass of air in cylinder and temperature.

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## This note was uploaded on 02/24/2012 for the course MECHANICAL 2.611 taught by Professor Davidburke during the Fall '06 term at MIT.

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ps5_soln - 2.611 Fall 2006 Problem Set#5 Answer Key Problem...

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