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Unformatted text preview: 22.314/1.56/2.084/13.14 Fall 2006 Problem Set III Solution We will consider the primary stress and secondary stress. Since the primary stresses are defined as external stresses, the only primary stress for this problem is due to system pressure. The secondary stresses are due to constraint. For this problem, the secondary stresses are junction discontinuity stress and thermal stress. We consider the vessel subjected to static load and cyclic load respectively. 1. Under static load Given that σ y = 320 MPa and σ u = 500 MPa, from ASME code, we can get that under primary stress: 2 1 P m ≤ S m ≤ min ( σ y , σ u ) = 166 . 7 MPa 3 3 For cylinder: P m = | σ θ − σ r | = 11 P For sphere: P m = | σ θ − σ r | = 5 . 75 P Thus we have: 11 P ≤ 166 . 7 MPa P ≤ 15 . 6 MPa For secondary stresses, we will consider three regions, the cylinder region far from junction, the sphere region far from junction and junction region. The thermal stress is assumed identical in three regions. Define: identical in three regions....
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This note was uploaded on 02/24/2012 for the course MECHANICAL 2.084J taught by Professor Mujids.kazimi during the Fall '06 term at MIT.
- Fall '06