Intro atomic spec PPT v4 0

# Intro atomic spec PPT v4 0 - Page ‹#› Partial Energy...

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Unformatted text preview: Page ‹#› Partial Energy Level Diagrams 610 nm Lithium Lithium 323 nm 460 nm 671 nm Sodium Sodium 589 / 590 nm 819 nm 330 nm 404 nm 767 / 769 nm Potassium Potassium 694 nm Page ‹#› Gas Mixtures Maximum Temperatures, °C Air-Coal Gas 1825 Air-Propane 1725 Air-Hydrogen 2045 Air-Acetylene 2250 Oxygen-Hydrogen 2677 Oxygen-Acetylene 3060 Nitrous Oxide- Acetylene 2955 Argon-Hydrogen- Entrained Air 1577 surrounding air secondary combustion zone interconal zone primary combustion zone preheat zone Page ‹#› Maxwell-Boltzmann Equation: N 1/ N (nm) Energy (eV) g 1 /g 2000 K 3000 K 4000 K Cs 852.1 1.46 2 4.44 X 10- 4 7.24 X 10- 3 2.98 X 10- 2 Na 589.0 2.11 2 9.86 X 10- 6 5.88 X 10- 4 4.44 X 10- 3 Ca 422.7 2.93 3 1.21 X 10- 7 3.69 X 10- 5 6.04 X 10- 4 Zn 213.8 5.80 3 7.29 X 10-15 5.38 X 10-10 1.48 X 10- 6 N 1 N = g 1 g e ! ( E 1 ! E ) / kT The 228.8 nm line of Cadmium corresponds to the 1 S- 1 S 1 transition. Calculate the ratio of in air/ The temperature is 2250 °C or 2523 K Degeneracy ratio of the two levels is: g 1 / g = [2(1)+1]/[2(0)+1] =3/1 N 1 N C 2 H 2 First find the frequency of light at 228 nm so that the energy difference can be calculated from E = h ! ! = c " = 2.998 # 10 10 cm sec-1 2.288 # 10 \$ 5 cm = 1.310 # 10 15 sec \$ 1 N 1 N = g 1 g e ! ( E 1 ! E ) / kT Page ‹#› Find the energy difference between the levels: E 1 ! E = h " = (6.626 # 10 ! 27 erg- sec )( 1.310 # 10 15 sec ! 1 ) = 8.6828....
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Intro atomic spec PPT v4 0 - Page ‹#› Partial Energy...

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