March 11, 2009 - March 11, 2009 Reaction Initial and final...

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Unformatted text preview: March 11, 2009 Reaction Initial and final molecules have there own potential energies independent of path Energy of reaction lost (-) or added (+) is outside If A B H r = -100,000 A D C B H r = -100,000 Hess Law Find enthalpy (or energy) for any reaction via a path where enthalpies are known A 2 C H r = ? Know A 2B H r = +20KJ B C H r = -30KJ 2B 2C H r = -60KJ Add 1 + 3 A 2C +20 -60 = - 40KJ C(gr) C(dia) H r = ? Path burn both C(gr) + O 2 CO 2 H r = -400KJ C(dia) + O 2 CO 2 H r = -402KJ CO 2 C(dia) + O 2 H r = +402KJ Add 1 + 3 C(gr) C(dia) H r = +402 -400 = +2KJ 2A 1B H r = -20,000 @ 300K What is H r at 400K ? 2A B 400K | | 2A B 300K 3 step path 1. Cool A from 400 to 300 H = 2C p (300 -400) = -2C p (100) If 2C p (A) = 60, H = -6000 2. React at 300K 2A B H r = -20,000J 3. Heat B from 300K to 400K...
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This note was uploaded on 02/26/2012 for the course CHEM 108 taught by Professor Dr.brennan during the Spring '09 term at Binghamton University.

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March 11, 2009 - March 11, 2009 Reaction Initial and final...

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