Solutions for Examples for 10-6-10 (1)

Solutions for Examples for 10-6-10 (1) - Examples for...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Examples for 10-6-10 1. Jake is deciding what to do with his Friday night. In the past he went to the bar with friends with a probability of .2, and the rest of the time he went to the girlfriend’s house. If he was at the bar, he went home with 70% of the time, and he went to jail the rest of the time. If he was at the girlfriend’s house, he went home only 10% of the time, and he stayed the rest of the time. If he went to the bar and then home, he was happy 95% of the time. If he went to the bar and jail, he was happy only 1% of the time. 18% of all Friday nights, Jake went to the girlfriend’s house, stayed, and was happy about it. 4.8% of all Friday nights, Jake went to his girlfriend’s house, went home afterward, and was happy about it. Use the past information provided to find the following probabilities: P(Jail) P(Jail) = P(Bar) * P(Jail | Bar) = .2*.3 = .06 (This uses the general multiplication rule). P(Home) P(H) = P(B)*P(H | B) + P(GF)*P(H | GF) = .2*.7 + .8*.1 = .22 (This uses the law of total probability). P(Girlfriend’s | Home)
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

Solutions for Examples for 10-6-10 (1) - Examples for...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online