Homework 3 ME 113 Spring 2011 solution

Homework 3 ME 113 Spring 2011 solution - Homework 3 Due...

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Homework 3 Due February 17 by 2:00 1. T , ° C P , kPa v , m 3 / kg Phase description 50 12.35 7.72 Saturated mixture 143.6 400 0.4624 Saturated vapor 250 500 0.4744 Superheated vapor 110 350 0.001051 Compressed liquid 2. P , kPa T , o C v , m 3 /kg h , kJ/kg Condition description and quality, if applicable 200 120.2 0.8858 2706.3 x = 1, Saturated vapor 270.3 130 1959.3 x = 0.650, Two-phase mixture 201.8 400 1.5358 3277.0 Superheated vapor 800 30 0.001004 * 125.74 * Compressed liquid 450 147.90 - - Insufficient information 3. T, ° F P, psia h , Btu / lbm x Phase description 65.89 80 78 0.566 Saturated mixture 15 29.759 69.92 0.6 Saturated mixture 10 70 15.35 - - - Compressed liquid 160 180 129.46 - - - Superheated vapor 110 161.16 117.23 1.0 Saturated vapor
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4. 5. Answer: m=145 kg
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6. (use generalized compressibility chart – there isn’t a special one for nitrogen)
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7. A piston-cylinder device that is filled with water is cooled. The final pressure and volume of the water are to be determined. Analysis
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Homework 3 ME 113 Spring 2011 solution - Homework 3 Due...

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